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2x^2-x=10000
We move all terms to the left:
2x^2-x-(10000)=0
We add all the numbers together, and all the variables
2x^2-1x-10000=0
a = 2; b = -1; c = -10000;
Δ = b2-4ac
Δ = -12-4·2·(-10000)
Δ = 80001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{80001}=\sqrt{9*8889}=\sqrt{9}*\sqrt{8889}=3\sqrt{8889}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-3\sqrt{8889}}{2*2}=\frac{1-3\sqrt{8889}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+3\sqrt{8889}}{2*2}=\frac{1+3\sqrt{8889}}{4} $
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